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2x^2-138x+2160=0
a = 2; b = -138; c = +2160;
Δ = b2-4ac
Δ = -1382-4·2·2160
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-138)-42}{2*2}=\frac{96}{4} =24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-138)+42}{2*2}=\frac{180}{4} =45 $
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